Solve the equation p^2 + 2p - 8 = 0 using quadratic formula

p = 2        p = -4

Step-by-step explanation:

Find the solution for p^2+2p-8=0

using the Quadratic Formula where

a = 1, b = 2, c = -8

p = -b ±√(b^2 - 4ac)/2a

p = -2±√(2^2 - 4(1)(-8))/2(1)

p = -2±√(4 - (-32))/2

p = -2±√(36)/2

The discriminant b^2 - 4ac > 0

So, there are two roots.

Simplifying the radical

p = -2±6/2

p = -2+6/2 = 2

and

p = -2-6/2 = -4

i dont have an answer

step-by-step explanation: