At 2: 45 p. m., a jet is located 56 mi due east of a city. a second jet is located 30 mi due north of the city. to the nearest tenth of a mile, what is the distance between the two jets?

The answer is:

The distance between the two jets is 63.5 mi.

From the statement we know that the first jet is located 56 mi due to the east city while the second jet is located 30 mi due to the north, so, we can calculate the distance between the two jets using the Pythagorean Theorem.

The Pythagorean Theorem states that:

So,

Hence, the distance between the two jets is 63.5 mi.

Have a nice day!

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

hi there!

step-by-step explanation:

a roof pitch is basically for every inch rise there is 12 inches run.

the height of the roof is also known as the rafter.

formula: rafter^2 = rise^2 + run^2

rafter^2 = 5^2 + 12^2

rafter^2 = 25 + 144

rafter ^2 = 169"^2

the height of the roof from the lowest point to the highest point is 169"^2.

hope this : )