The area of the indoor sports exhibition is shown below.

what is its perimeter? m ?

what is its area? m2 ?

Step-by-step explanation:

First, you need to make these conversions:

(Remember that )

4,000 cm to m:

700 cm to m:

You can observe in the figure that it is formed by  two rectangles and a semi-circle.

To calculate the perimeter, you need to add the exterior measures of each figure.

Remember that the circumference of a circle is:

Where "r" is the radius

Therefore, the perimeter is:

To find the area of the indoor sports exhibition, you need to add the areas of the rectangles and the area of the semi-circle.

The area of a rectangle can be calculated with:

Where "l" is the lenght and "w" is the width.

The area of a semi-circle can be calculated with:

Where "r" is the radius.

Then, the area of the indoor sports exhibition  is:

squares, rhombus, rectangles

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.