What is the value of the positive zero of the function , f, defined by f(x) =x^2-121

The positive zero is 11

Step-by-step explanation:

Given in the question an equation,

f(x) =x² - 121

We are asked to find the positive zero of f(x)

means x > 0 for which f(x) = 0

so,

 x² = 121

Take square root on both sides of the equation

√x² = √121

  x =  ±11

which means that x = 11 and x = -11

Since x > 0 so we will reject x =-11 and we will accept x = 11

11

Step-by-step explanation:

You need to substitute into the function given:

Now you need to solve for the variable "x", to do this, first you must add 121 to both sides of the function:

Now apply square root to both sides of the function. Then, you get:

The value of the positive zero of the function is 11.

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²