Describe how you would graph this line using the slope-intercept method. be sure to write in complete sentences. -(2/3)x + 490

The slope-intercept form is: y = mx + b  (m is the slope, b is the y-intercept [where x = 0 or (0 , y)])

Based on the equation, the y-intercept is 490, or (0, 490)

The slope is -2/3x

How slopes work >  [when you have a negative slope(-2/3x), you move down 2 units and to the right 3 units. when the slope is positive(pretend -2/3x is 2/3x), you move up 2 units, and to the right 3 units. The numerator tells you how many units you need to move to (-)down or (+)up, the denominator tells you how many units you need to move to the right]

To graph this line, I would start at the point (0, 490) or the y-intercept, then from that point I would begin using the slope to go down 2 units, and to the right 3 units to get a few points, such as (3, 488) and (6, 486)etc, and then draw a line through the points (hope this was helpful)

y=mx+b slope intercept form

m=slope

b=y-intercept

equation given;

y=(-2/3)x+490

So this tells us the graphed equation will have a decreasing slope of 2/3, so for every unit distance the line rises by 2 and runs by 3 units, and the line will cross the y-axis at (0,490) so now we just need to find where it crosses the x-axis then we can graph it easily. Substitute in the value of 0 for y into the given equation and solve for x. We get x=735 so that tells us at point (735,0) the line crosses the x-axis.

Any questions please feel free to ask. Thanks!

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d