Question 18 of 25
2 points
how many solutions does the following system of equations have
2v=5x+4
v=3.x + 2
oa. two
o b. zero
c. infinitely many
d. one

the ONE solution is (0, 2) (Answer D)

Step-by-step explanation:

Please fix up the formatting a bit:

2v=5x+4

v=3.x + 2

becomes:

2v = 5x + 4

  v = 3x + 2

Multiplying all terms of the 2nd equation by -2, we get:

-2(v = 3x + 2), or -2v = -6x - 4

Combining this result with the first equation, we get:

2v = 5x + 4

-2v = -6x - 4

  0 = -x + 0

Then x must = 0.  Subbing this x value into the 2nd equation, we get:

v = 3(0) + 2.  Thus, v = 0, and the ONE solution is (0, 2).

d

step-by-step explanation:

i used the pitagoras theoreme

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: