Agroup of 10 students participate in chess club, karate club, or neither. let event a = the student is in karate club. let event b = the student is in chess club.

one of these students is randomly selected. what is p(a/b)?

option A

2/4 = 0.5

Step-by-step explanation:

Given in the questions that,

number of student in chess club = 4

P(B) = 4/10

number of student in karate club = 6

P(A) = 6/10

number of students who are both in chess and karate club = 2

P(A∩B) = 2/10

total number of students 10

Formula to use

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)