The probability that traffic lights on a certain road will be green is 0.6. when a driver on that road approaches two traffic lights in a row, x is the number of traffic lights that are green. what is p(x=1)? enter your answer, as a decimal, in the box. p(x=1) =

There are two possible ways for X=1: first light is green and second is red OR first light is red and second is green. The probabilities for these two options are to be summed: 0.6*0.4 + 0.4*0.6 to give the probability of exactly one light being green, namely 0.48.

The answer is 0.48

Step-by-step explanation:

I just took the quiz and it was correct

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.