The city zoo collected $100 in one morning. an adult ticket is $5 each, and a child's ticket is $3. how many different combinations of adult and children's tickets would have totaled $100?
5
6
7
8

6 combinations

Step-by-step explanation:

Let

x----> the number of adult tickets

y---> the number of a child tickets

we know that

5x+3y=100 ----> linear equation that represent the situation  

y=-(5/3)x+(100/3)

The maximum number of adult tickets is 20 (20*$5=$100)

The maximum number of a child tickets is 33  (33*$3=$99)

Construct a table for different values of x and find the values of y

The possible combinations will be pairs of whole numbers

see the attached table

The solution is 6 combinations