Which equation represents the line that has a slope of -2 and passes through the point (6,5)
a.) y = -2x - 17
b.) y = -2x - 16
c.) y = -2x + 16
d.) y = -2x + 17

d)  y = -2x + 17.

Step-by-step explanation:

Use the point-slope for  of the equation of a line:

y - y1 = m(x - x1)  where m = the slope and (x1, y1) is a point on the line.

So here we have:

y - 5 = -2(x - 6)

y = -2x + 12 + 5

y = -2x + 17.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

7,24

step-by-step explanation: