Find the exact area of a circle having the given circumference. 3pi

A = (9/4)*pi units^2

Step-by-step explanation:

The equation for the circumference of a circle is C = 2*pi*r, where r is the radius.  Given that the actual value of the circumference is 3 pi, we equate this 3 pi to 2*pi*r:  3 pi = 2*pi*r.  

Dividing both sides of this equation by pi, we get 3 = 2r, so that r = 3/2.

The formula for the area of a circle of radius r is A = pi*r^2.

Here r = 3/2, so the area of this circle is

A = pi*(3/2 units)^2 = pi(9/4) units^2, or   A = (9/4)*pi units^2.

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation: