When simplified and written in standard form, which quadratic function is equivalent to the polynomial shown?
2 + 7c – 4c2 – 3c + 4

2c^2 - 2c - 3

Step-by-step explanation:

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Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:

                                                     2  + 4c and -4c^2 + 4  Then we have:

-4c^2 + 4c + 6

We should reduce this by factoring -2 out of all three terms:

2c^2 - 2c - 3  This is the desired quadratic in standard form.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°