Amother who is 40 years old has a daughter and a son. the son is twice as old as the daugther. in 15 years the sum of all their ages will be 100 years. how old are the siblings now?

The son's age is 10 and the daughter's age is 5 now

Step-by-step explanation:

Let

x> the son's age now

y> the daughter's age now

we know that

x=2y > equation A

(x+15)+(y+15)+(40+15)=100

x+y+85=100

x+y=15 > equation B

Substitute equation A in equation B and solve for y

2y+y=15

3y=15

y=5 years

Find the value of x

x=2(5)=10 years

therefore

The son's age is 10.

The daughter's age is 5

answer: -8.2562234e+13

1 3 5

step-by-step explanation:

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