Ytterbium decays 50% every 4.2 days. how much of an 80g sample would be left after 54.6 days? use exponential decay formula.
a. 67 g
b. 53,211.33 g
c.41.76 g
d. 9.80 g
e. 0.12 g

Option E

Step-by-step explanation:

The exponential decay formula is:

Where p is the initial amount of Ytterbium

r is the rate of decrease

C(t) is the amount of Ytterbium in grams as a function of time

t is the time in days

In this problem:

t is the time in units of 4.2 days

Then

We want to calculate the amount of Ytterbium in 54.6 days.

Then as t is the time in units of 4.2 days

Finally

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

1st part is 64,000,000

2nd part 500,000

step-by-step explanation: