Perry’s pizza parlor sells pepperoni pizza for $1.15 per piece and plain pizza for $0.90. paul purchased 37 pieces of pizza for pam’s party, paying $39.05. how many pieces of pepperoni pizza did paul purchased?

Paul purchased 23 pieces of pepperoni pizza

Step-by-step explanation:

Let pepperoni pizza pieces = x

and plain pizza pieces  = y

So, the equations will be:

AS pepperoni pizza piece is sold for $1.15 and plain pizza is sold for $0.90 and Paul paid $39.05

1.15 x + 0.90 y = 39.05    eq(1)

Paul bought total 37 pieces of pizza so,

x + y = 37      eq(2)

Solving eq(1) and (2)  we can find the pieces of pepperoni pizza bought by Paul.

Multiplying equation (2) with 1.15 and subtracting eq(1) and eq(2)

1.15 x + 0.90 y = 39.05

1.15 x + 1.15 y = 42.55

-         -              -

0 x - 0.25 y = -3.5

y = -3.5/-0.25

y = 14

Putting value of y in equation(2)

x+y = 37

x + 14 = 37

x = 37 - 14

x = 23

So, Paul purchased 23 pieces of pepperoni pizza as x represents pepperoni pizza pieces.

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.