How do i solve this?

a football punted upward has a trajectory given by the equation y = 48x − 16x2, where y represents the football's height x seconds after it has been kicked. what is the maximum height, in feet, attained by the ball?

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The maximum happens at x = -b/2a

x = -48/2(-16) = 3/2

Now replace x in the equation and solve for y:

y = 48(3/2) - 16(3/2)^2

y =  -72 - 36

y = 36

The maximum height is 36 feet.

goog may have it for you

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.