How do i solve this?

a quadratic function is shown.

f(x) = 3x² + 30x + 27

what is the minimum value of this function? (hint: complete the square)

The minimum  happens at x = -b/2a

x = -30 / 2(3) = -30/6 = -5

Now replace x in the equation with -5 and solve:

3(-5)^2 + 30(-5) +27 = 75 - 150 + 27 = -48

The minimum is at (-5,-48)

the answer is b.)

< 1=< 2