For 20 points!
let z=13+7i and w=3(cos(1.43)+isin(1.43)
a. convert zw using de moivre's theorem
b. calculate z/w using de moivre's theorem

a)zw  = 44.295 cos(1.924) +isin(1.924))

b) z/w= 4.921 cos(-0.936) + isin(-0.936)

Step-by-step explanation:

Given:

z=13+7i

w=3(cos(1.43)+isin(1.43)  

a. convert zw using De Moivre's theorem  

First coverting z into  polar form:

13^2 + 7^2  = 14.765

=r

θ= arctan (7/13)

 = 0.49394                            (28.301 in degrees)

z= 14.765(cos(0.49394)+isin(0.49394)  )

Now finding zw

zw= 14.765(cos(.494)+isin(.494))×3(cos(1.43)+isin(1.43))

Using De Moivre's theorem, the modulus will be multiplied

14.765 x 3=44.295

whereas the angles will be added

.494+1.43=1.924

Thus:

zw  = 44.295 cos(1.924) +isin(1.924))

b)

finding z/w

z/w= 14.765(cos(.494)+isin(.494)) / 3(cos(1.43)+isin(1.43))

Using De Moivre's theorem, the modulus will be divided

14.765 / 3 = 4.921

whereas the angles will be subtracted:

.494-1.43=-0.936

Thus:

z/w= 4.921 cos(-0.936) + isin(-0.936) !

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.