What is the solution to the set of equations in the form (a, b)

a-3b=16
a=b-2

(-11, - 9)

Step-by-step explanation:

Given the 2 equations

a - 3b = 16 → (1)

a = b - 2 → (2)

Substitute a = b - 2 into (1)

b - 2 - 3b = 16

- 2b - 2 = 16 ( add 2 to both sides )

- 2b = 18 ( divide both sides by - 2 )

b = - 9

Substitute b = - 9 into (2) for the corresponding value of a

a = - 9 - 2 = - 11

Solution is (- 11, - 9)

idk

step-by-step explanation: i just don't