Which is the equation in slope-intercept form for the line that passes through (-1,5) and is parallel to 3x + 2y = 4?

a. y = 2/3x + 7/2
b. y = -2/3x + 7/2
c. y = 3/2x - 7/2
d. y = -3/2x + 7/2

-3/2x + 7/2

Step-by-step explanation:

for parallel lines; m₁ = m₂

the gradient of the given line is -3/2

2y= -3x + 4

y = -3/2x + 2

therefore the gradient of the parallel line is -3/2

hence the equation is y-y₁ = m(x-x₁)

y-5 = -3/2(x+1)

y - 5 =-3/2x - 3/2

y = -3/2x -3/2 + 5

y = -3/2x + 7/2

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}