The quotient of (x^5-3x^3-3x^2-10x÷15) and a polynomial is x^2-5. ahat is the polynomial

x^7-8x^5-3x^4+5x^3+30x^2+50x-75

That would be the final answer.

Step-by-step explanation:The operation this problem requires is multiplication. In this case, you need to multiply the quotient by the huge polynomial given. 

The problem will be: (x^2-5)(x^5-3x^3-3x^2-10x+15)

When it comes to this, you have to distribute. First you need to distribute the x^2 to the big polynomial, then distribute the -5 to the big polynomial. After that you have to combine the two big polynomials into one by combining the like terms. 

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐