Acircular cake with a radius of 8 inches is cut from the center into 6 equal pieces. how many inches wide, to the nearest tenth of an inch, is the outer edge of each piece of cake?

8.4 inches.

Step-by-step explanation:

We know that the circumference of a circle can be calculated with this formula:

Where "r" is the radius of the circle.

We know that the circular cake (whose radius is 8 inches) is cut from the center into 6 equal pieces. Then, you need to divide the circumference of this circular cake by 6 to find the width of the outer edge of each piece of cake.

Therefore, this is (to the nearest tenth of an inch):

The width of the outer edge of each piece of cake  8.4 inches.

SOLUTION:

Given, a circular cake with a radius of 8 inches is cut from the center into 6 equal pieces. We have to find the width of the outer edge of each piece of cake.

We know that the circumference of a circle can be calculated with this formula: where "r" is the radius of the circle.

We know that the circular cake (whose radius is 8 inches) is cut from the center into 6 equal pieces.

Then, you need to divide the circumference of this circular cake by 6 to find the width of the outer edge of each piece of cake.

Therefore, this is (to the nearest tenth of an inch):

Hence, the cake piece is 8.4 inches wide.

518,400

step-by-step explanation:

the area is multiplying all the given measurements together.

40 * 18 * 30 * 24 = 518,400

answer: add the !

step-by-step explanation: then we will answer