The equation of the line that passes through points (0,-7) and (2,-1) is shown below. what value is missing from the equation?

For this case we have that by definition, the slope-intersection equation of a line is given by:

Where:

m: It's the slope

b: It is the cutoff point with the y axis

Thus, the equation is:

Substituting a point we find b:

Finally the equation is:

The missing value is 3

The value of missing is 3

Step-by-step explanation:

* To form an equation of a line from two points on the line, you

  must find the slope of the line at first

- The form of the equation is y = mx + c, where m is the slope of the

 line and c is the y-intercept

- The rule of the slope of a line passes through point (x1 , y1) and (x2 , y2)

  is m = (y2 - y1)/(x2 - x1)

* Lets solve the problem

∵ (0 , -7) and (2 , -1) are tow points on the line

- Let (0 , -7) is the point (x1 , y1) and (2 , -1) is the point (x2 , y2)

∴ m = (-1 - -7)/(2 - 0) = (-1 + 7)/2 = 6/2 = 3

- Lets write the equation

∴ y = 3x + c

- c is the y-intercept means the line intersect the y-axis at point (0 , c)

∵ Point (0 , -7) on the line

∴ The line intersect the y-axis at point (0 , -7)

∴ The y-intercept is -7

∴ The equation of the line is y = 3x - 7

* The value of missing is 3

irrational, cannot