Evaluate (2-5i)(p+q)(i) when p=2 and q=5i.

Step-by-step explanation:

We have the product of 2 complex numbers

We know that:

Then we substitute these values in the expression

The product of a complex number by its conjugate is always equal to:

Then

Remember that:

So

Finally

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option