∆abc has vertices at a(12, 8), b(4, 8), and c(4, 14).
∆xyz has vertices at x(6, 6), y(4, 12), and z(10, 14).
∆mno has vertices at m(4, 16), n(4, 8), and o(-2, 8).
∆jkl has vertices at j(14, -2), k(12, 2), and l(20, 4).

1) are congruent. a is a single rigid transformation that maps the two congruent triangles.

1) a. triangle abc and triangle xyz
b. triangle abc and triangle mno
c. triangle jkl and triangle abc
d. triangle mno and triangle xyz

2) a. reflection
b. dilation
c. rotation
d. translation

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

this equation is in point-slope form.

where,

using this equation you can gather a point and the slope, which gives you enough information to draw a line. transform the equation to standard form to start.

the equation is now in standard form, we have a point, as well as the slope:

point: (0, -6)

slope: -2

plot (0,-6), then simply rise/run with the provided slope of -2, once you feel you have a comfortable amount of points - draw a line.

answer is d. (5, 3); 8. hope you got it down bud.