Let a and b be rational numbers. then by definition
a = m/n and b = p/p where m, n, p, and q are integers
xy=m/n × p/q
ng
so xy is the quotient of two integers.
this proof shows that the product of two rational numbers
a. an integer
b. irrational
c. rational
d. a whole number

The product of two rational numbers is a rational number

Step-by-step explanation:

I'll quickly recap the proof: a rational number is, by definition, the ratio between two integers. So, there exists four integers m,n,p,q such that

If we multiply the fractions, we have

Now, mp and nq are multiplication of integers, and thus they are integers themselves. So, ab is also a ratio between integer, and thus rational.

the product of two rational numbers is a rational number!

Step-by-step explanation:

i pretty sure it is

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.