The length of a rectangle is 2 cm more than four times the width. if the perimeter of the rectangle is 84 cm, what are its dimensions

Length 34 cm

Width 8 cm

Step-by-step explanation:

Let

x> the length of the rectangle

y> the width of the rectangle

we know that

The perimeter of rectangle is equal to

P=2(x+y)

P=84 cm

so

84=2(x+y)

42=x+y > equation A

x=4y+2 > equation B

substitute equation B in equation A and solve for y

42=(4y+2)+y

5y=42-2

y=40/5=8 cm

Find the value of x

x=4y+2 > x=4(8)+2=34 cm

The dimensions are

Length 34 cm

Width 8 cm