Tb'(4, -8) was transformed using the translation (x - 2, y + 3). what were the coordinates of b?

(6, -11)

Step-by-step explanation:

The translation (x-2,y+3) means "subtract 2 from x coordinate" and "add 3 to the y coordinate".

After the transformation, we have the point B'(4,-8). Which point, let it be (x,y), after being transformed is B'(4,-8)??

According to the transformation rule, we have to "subtract 2 from x coordinate" and "add 3 to the y coordinate", thus

x-2=4

x=4+2

x=6

and

y+3=-8

y=-8-3

y=-11

THe coordinate of B are (6,-11)

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i