Franco is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. the shape of his satellite can be modeled by y^2+6y-3x+3=0, where x and y are modeled in inches. he realizes that the static is a result of the feed antenna shifting slightly off the focus point. what is the focus point of the satellite?

focus point of  satellite is (-125,-3)

Step-by-step explanation:

The question is on finding the focus point of a parabola

Given y²+6y-3x+3=0

Rewrite the equation

y²+6y=3x-3

Complete square on both sides

y²+6y+9=3x-3+9

Factorize

(y+3)²= 3x+6(a)

(y+3)²= 3(x+2)

Compare  equation (a) to standard equations for parabola

(y+3)²= 3(x+2)

(y-b) ²= 2p(x-a)(b)

2p=3divide both sides by 2

p=3/2

Vertex (a,b)=( -2,-3)from equation (b)

Focus point is given by  (a+p/2 , b)(c)

Substitute values in equation c above;

(-2+3/4 , -3) = (-5/4 ,-3) =(-1.25, -3)

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m