Could i get some on these two trig problems?

state the trigonometric ratios for the triangle below.

sin θ = 12/13 cos θ = 5/13 tan θ = 12/5

sin θ = 12/5 cos θ = 5/13 tan θ = 12/13

sin θ = 5/13 cos θ = 12/13 tan θ = 5/12

sin θ = 5/13 cos θ = 12/13 tan θ = 12/5

state the trigonometric ratios for < a in the triangle below.
sin a = 4/5 cos a = 3/5 tan a = 4/3

sin a = 3/5 cos a = 4/5 tan a = 4/3

sin a = 3/5 cos a = 4/3 tan a = 4/5

sin a = 3/5 cos a = 4/5 tan a = 3/4

Part 1) Sin ϴ = 5/13, Cos ϴ = 12/13, Tan ϴ = 5/12

Part 2) Sin A = 4/5, Cos A = 3/5,Tan A = 4/3  

Step-by-step explanation:

we know that

In a right triangle

The function sine of an angle is equal to divide the opposite side to the angle by the hypotenuse

The function cosine of an angle is equal to divide the adjacent side to the angle by the hypotenuse

The function tangent of an angle is equal to divide the opposite side to the angle by the adjacent side to the angle

Part 1)

Find the Sin ϴ

Sin ϴ=5/13

Find the Cos ϴ

Cos ϴ=12/13

Find the Tan ϴ

Tan ϴ=5/12

Part 2) we know that

In the right triangle ABC

Applying the Pythagoras Theorem

Find the hypotenuse AB

Find the Sin A

Sin A=8/10=4/5

Find the Cos A

Cos A=6/10=3/5

Find the Tan A

Tan A=8/6=4/3

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)