the scale of a map is 1 inch : 9.5 miles.

a) the actual distance between joseph's house and the airport is 24 miles. how far apart are joseph's house and the airport on the map?

b) joseph traveled from his house to the airport. he then traveled another 16 miles past the airport to a restaurant. how many inches on the map represent this distance?

Part a) The distance on a map between Joseph's house and the airport is 2.53 inches

Part b) The distance on a map between the airport and the restaurant is 1.68 inches and the total distance on a map between Joseph's house and the restaurant is 4.21 inches

Step-by-step explanation:

Part a) The actual distance between Joseph's house and the airport is 24 miles. How far apart are Joseph's house and the airport on the map?

we know that

The scale of a map is 1 inch : 9.5 miles

so

using proportion

Find the distance on a map if the  actual distance between Joseph's house and the airport is 24 miles

Let

x> the distance on a map

1/9.5=x/24

x=24/9.5=2.53 inches

Part b) Joseph traveled from his house to the airport. He then traveled another 16 miles past the airport to a restaurant. How many inches on the map represent this distance?

we know that

The scale of a map is 1 inch : 9.5 miles

so

using proportion

Find the distance on a map if the  actual distance between airport to the restaurant is 16 miles

Let

x> the distance on a map

1/9.5=x/16

x=16/9.5=1.68 inches

The total distance on a map between Joseph's house and the restaurant is equal to

2.53 inches+1.68 inches=4.21 inches

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

-2 is the right