Integers

q1 write a pair of integers

a) product is -10
b)sum is -5
c)difference is -2
d)difference is 4
e)sum is -9 and product -10
f) integers a and b such that a÷b=-4

a) -2 and 5

b) 2 and -7

c) 2 and 4

d) 2 and 6

e) idk (think is mean sum -10 and product is 9 which is -1 and -9

f) -16 and 4

a) -2 and 5

b) 2 and -7

c) 2 and 4

d) 2 and 6

e) idk (think is mean sum -10 and product is 9 which is -1 and -9

f) -16 and 4

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116