In school 40% of the students play tennis, 24% of the students play baseball, and 58% of the students playing neither tennis or baseball, if you pick a student at random what is the probability that the student plays both tennis and baseball

 The required probability that the random student selected plays both tennis and basketball is 22%.

Step-by-step explanation:  Given that in a school, 40% of the students play tennis, 24% of the students play baseball, and 58% of the students playing neither tennis or baseball.

We are to find the probability that a random student picked plays both tennis and basketball.

Let the total number of students in the school be 100. Also, let T and B represents the set of students who play tennis and basketball respectively.

Then, according to the given information, we have

The number of students who play either tennis or basketball will be represented by T ∪ B.

And so, we have

We know that the number of students who play both tennis and basketball is denoted by T ∩ B.

From set theory, we get

Thus, the required probability that the random student selected plays both tennis and basketball is 22%.

i'm sure goog can you get that answer

i think 5 miles per hour

step-by-step explanation: