Ahawk flying at a height of 60 feet spots a rabbit on the ground. if the hawk dives at a speed of 55 feet per second, how
long will it take the hawk to reach the rabbit?
(hint: a model for the vertical motion of a projected object is given by the equation h = -16t2 + vt + s, where h is the height
in feet, t is the time in seconds, v is the initial velocity in feet per second, and s is the starting height of the object in feet. use
this equation to find the time taken by the hawk to reach the rabbit.

The hawk reaches the rabbit at t=4.3 sec

Step-by-step explanation:

Let

h ----> is the height in feet

t ----> is the time in seconds

v ---> the initial velocity in feet pr second

s ----- is the starting height

we have

when the hawk reaches the rabbit the value of h is equal to zero

we have

substitute

Solve the quadratic equation by graphing

The solution is t=4.3 sec

see the attached figure

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.