Rationalise the denominator 5 by√7-√5

⇛{5(√7+√5)}/2.

Step-by-step explanation:

Given,

5/(√7-√5)

The denominator is √7-√5.

We know that

The rationalising factor of √c-√a is √c+√a.

Therefore, the rationalising factor of √7-√5 is √7+√5. To rationalise the denominator of 5/(√7-√5), we multiply this by (√7+√5)/(√7+√5).

⇛{5/(√7-√5)}/{(√7+√5)/(√7+√5)}

⇛{5(√7+√5)}/{(√7-√5)(√7+√5)}

⇛{5(√7+√5)}/{(√7)²-(√5)} [∵ (a-b)(a+b)=a²-b²]

⇛{5(√7+√5)}/{(√7*7)-(√5*5)}

⇛{5(√7+√5)}/(7-5)

⇛{5(√7+√5)}/2

Hence, the denominator is rationalised.

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rationalise the denominator 1/√20..

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g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)