How do i multiply problems such as (x+1) (3x^2-4x+6) ?

Try using the box method. When I do it, it makes multiplying trinomials and binomials like these easier.

Here is how I would set up the equation:

as you can see in the picture below I multiplied x by 3x^2, -4x, and positive six which gives me a product of 3x^3 (when multiplying always add the exponents) -4x^2 and 6x. Afterwards I did the same thing by multiplying one to the trinomials (3x^2, -4x and 6). Now to simplify the answer you will add by like terms. So -4x^2 plus 3x^2= -x^2

6x+(-4x)= 2x. Since the only two numbers left (6 and 3x^3 aren’t like terms, you leave it like that. Your answer will be 3x^3 + (-x^2)+2x+6.

other answer is correct. i had used the radius of the radius somehow. a website:

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus