Given cos alpha=15/17 in q1, find cos(alpha/2) and sin(alpha/2)

• cos(α/2) = (4/17)√17

• sin(α/2) = (√17)/17

Step-by-step explanation:

The appropriate hαlf-angle identities are:

sin(α/2) = √((1 -cos(α))/2)

cos(α/2) = √((1 +cos(α))/2)

Putting in your given values for cos(α), we have ...

cos(α/2) = √((1 +15/17)/2) = √(16/17) = 4(√17)/17

sin(α/2) = √((1 -15/17)/2) = √(1/17) = (√17)/17

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

because that’s us why