Ten slips of paper labeled from 1 to 10 are placed in a hat. the first slip of paper is not replaced before selecting the second slip of paper. what is the probability of selecting a multiple of 3 and then a multiple of 4?

3/50
1/10
2/45
1/15

Step-by-step explanation:

Multiples of 3 (from 1 to 10) are 3, 6, and 9.

Multiples of 4 (from 1 to 10) are 4 and 8.

First,

Probability of selecting multiple of 3 from 10 total slips are 3/10

now since it is not replaced, we have to now think that there are 9  total slips.

Second,

Probability of selecting multiple of 4 from 9 total slips are 2/9

in probability "AND" means multiplication. Hence,

selecting 3 "AND" then selecting 4 means, we need to multiply the individual probabilities found.

So,

3/10 * 2/9 = 1/15

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )