Find the equation in standard form of the line parallel to y=-1/5x+7 and passing through the point (-10,-3)

the desired equation is y = (-1/5)x - 5.

Step-by-step explanation:

Parallel lines have the same slope.  Here that slope is -1/5.

Let's use the slope-intercept form of the equation of a straight line:

y = mx + b

We know this new line passes through (-10, -3).  Substitute -3 for y in y = mx + b, as well as -10 for x and -1/5 for m:

-3 = (-1/5)(-10) + b and solve for b:

-3 = 2 + b.  Then b = -5, and the desired equation is y = (-1/5)x - 5.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

step-by-step explanation: