Identify the vertex and the y-intercept of the graph of the function y=-2(x+3)^2 +2.

we can simplify it to this:

so we know it , the intercept in a standard equation of a parabola is C:

so the intercept is (-16) and for the vertex use:

x=-b/2a

so now put it in the equation and get the y of vertex:

y=-18+36-16=2 ==>vertex(-3,2)

do it yourself this is easy

step-by-step explanation:

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)