Me what is the y-value in the solution to this system of linear equations? 4x + 5y = −12 -2x + 3y = −16 a.) −4 b.)−2 c.)2 d.)5

To solve, use the substitution method.

4x + 5y = -12

Move the variable to the right and change sign.

4x = -12 - 5

Divide both sides of the equation by 4.

x = -3 - 5/4y

Substitute the given value of x into the lower equation.

-2 (-3 - 5/4y) + 3y = -16

Distribute -2 through the parenthesis.

6 + 5/2y + 3y = -16

Add like terms.

6 + 11/2y = -16

Use inverse operations to multiply both sides by 2.

12 + 11y = -32

Move the constant to the right side.

11y = -32 - 12

Solve.

11y = -44

Divide both sides by 11.

y = -4 (your answer)

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,