If h(x) = 3x − 1 and j(x) = −2x, solve h[j(2)] and select the correct answer below. -11 11 -13 13

- 13

Step-by-step explanation:

To evaluate h(j(2)) substitute x = 2 into j(x) then substitute the value obtained into h(x)

j(2) = - 2 × 2 = - 4, then

h(- 4) = (3 × - 4) - 1 = - 12 - 1 = - 13

Hence h(j(2)) = - 13

its c or d   take a lucky guess my dude

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