What is the quotient (2x4 – 3x3 – 3x2 + 7x – 3) ÷ (x2 – 2x + 1)?

2x²+x-3. The quotient resulting of the division of the polynomial ÷ is 2x²+x-3.

In order to find the quotient we have to apply the division of the polynomial ÷ is 2x²+x-3.

We divide the first monomial of the dividend between the first monomial of the divisor .

(2x^{4})÷=

This result is put under the box and we multiply it by each term of the divisor polynomial and the result is subtracted in the polynomial dividend:

2x^4 -3x^3 -3x^2 +7x -3 ║ x^2 -2x +1

-2x^2+4x^3 -2x^2            ║ 2x^2+x-3 -----------> This is the quotient

            x^3 -5x^2 +7x  -3

           -x^3 +2x^2 -  x +0

                    -3x^2 +6x -3

                     3x^2 -6x +3

                                      0

The correct answer is,

2x² + x - 3

Step-by-step explanation:

It is given that,

(2x4 – 3x3 – 3x2 + 7x – 3) ÷ (x2 – 2x + 1)

To find the quotient

                                       2x² + x - 3

x² - 2x + 1  | 2x4 – 3x3 – 3x2 + 7x – 3

                  2x⁴ - 4x³ + 2x²              

                           x³ - 5x² + 7x

                           x³ - 2x² + x            

                                -3x² + 8x - 3

                                -3x² + 6x - 3

                                           2x

Therefore the quotient is   2x² + x - 3

step-by-step explanation: where's the phrase?