Solve 2x2 + 8 = 0 by graphing the related function.

The values of x are x= 2i and x= -2i

Step-by-step explanation:

We need to solve the equation:

2x^2 + 8 =0

Taking 2 common

2(x^2 +4) =0

Dividing both sides by 2

x^2+4 =0

Adding -4 on both sides

x^2 +4 -4 = 0-4

x^2 = -4

Taking square root on both sides we get

√x^2 = √-4

we know √4 = 2 and √-1 = i so answer is:

x = ± 2i

The values of x are x= 2i and x= -2i

The graph is shown in figure attached.

parallel and congruent

step-by-step explanation:

the movement of translation is linear.   these have the same translation because you are using the same rule for each point of the triangle so you will see the same slope being used to get from a point on the triangle to its image.

same slope!   you should think parallel when you see those 2 word together (well unless it's the same line but it can't be because we are coming from different points here)

congruent! because each point is being moved the same distance.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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