Anyone who could with this it would be amazingly appreciated.

The sum of angles in ΔABD is ...

  2a + b + d = 180

The sum of angles in ΔAHG is ...

  a + h + 90 = 180

Solving this second equation for a, we have ...

  a = 180 -90 -h = 90 -h

Substituting this into the first equation, we have ...

  2(90 -h) +b +d = 180

  180 -2h +b +d = 180 . . . . . eliminate parentheses

  b + d = 2h . . . . . . . . . . . . . add 2h-180

  h = (1/2)(b+d) . . . . . . . . . . divide by 2

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

unless if u could do my questions, if not i wouldn't want to