If f(x) = –2x+8 and g(x) = square root of x+7, what is (fºg)(2)

(fog)(2)=2

Step-by-step explanation:

Given

f(x)= -2x+8

and

g(x)= √(x+7)

For finding (fog)(2), we have to find (fog)(x) first

In order to find (fog)(x) we will put the value of g(x) in f(x) in place of x.

(fog)(x)= -2g(x)+8

Putting the value of g(x)  

(fog)(x)= -2√(x+7)+8

We have to find (fog)(2), so we have to put at the place of x in the composition

(fog)(x)= -2√(2+7)+8

(fog)(x)= -2√9+8

= -2(3)+8

= -6+8

=2

So,

(fog)(2)=2   ..

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

answer: i literally just answered this question but they want me to do it again

step-by-step explanation: