Ihave class in a half an hour and i still haven't solved all of the hw guys i'll give 90 points and brainliest for the first correct answer with brief explanation: you so much! given: e, f, q, d∈k(o),o ∈ ed, m∠dfq = 10°, measure of arc ef = 28° find: angles of △efq

Angles of △EFQ:

m<EFQ = 100°

m<EQF = 14°

m<FEQ = 66°

Step-by-step explanation:

ED is the diameter of the circle O

so m<EFD = 1/2 (180) = 90°

Given m∠DFQ = 10°

△EFQ

m<EFQ = m<EFD + m∠DFQ = 10° + 90° = 100°

arc EF = 28°,

so m<EQF = 1/2 (28) = 14°

m<FEQ = 180 - ( 100° +  14°) = 66°

m<EFQ = 100°

m<EQF = 14°

m<FEQ = 66°

5

step-by-step explanation: