What is the standard form of the equation of the circle in the graph? (x + 3)^2 + (y + 3)^2 = 3 x^2 + y^2 = 9 x^2 + y^2 = 3 (x + 3)^2 + (y + 3)^2 =9

B

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← where r is the radius

here r = 3 ⇒ r² = 9, thus

x² + y² = 9 ← equation of circle

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the infinity sign

step-by-step explanation: