A. f(x) = x2 – 11x – 12 b. f(x) = x2 – 4x –12 c. f(x) = x2 + x – 12 d. f(x) = x2 – x – 12 match each quadratic function given in factored form with its equivalent standard form listed on the left. f(x) = (x + 2)(x – 6) f(x) = (x – 4)(x + 3) f(x) = (x – 12)(x + 1) f(x) = (x – 3)(x + 4)

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

2425

step-by-step explanation:

you just switch the numbers basically so it would be 3/17