Aline has a slope of -4/5 . which ordered pairs could be points on a line that is perpendicular to this line? select two options. (–2, 0) and (2, 5) (–4, 5) and (4, –5) (–3, 4) and (2, 0) (1, –1) and (6, –5) (2, –1) and (10, 9)

The first pair (-2,0) and (2,5) and the last pair (2,-1) and (10,9)

Step-by-step explanation:

The perpendicular line has what is called a 'negative reciprocal slope'. This means you have to calculate -1 divided by the original slope.

For your line with slope -4/5, we're looking for a line with slope -1/(4/5) = 5/4.

Now we have to calculate the slope of each of the given pairs to find a match. We do this by dividing the y difference by the x difference.

(-2,0) and (2,5) -> slope is (5-0)/(2--2) = 5/4 Match!!

(-4,5) and (-3,4) -> slope is (4-5)/(-3--4) = -1/1 = -1 No match

(-3,4) and (2,0) -> slope is (0-4)/(2--3) = -4/5 No match

(1,-1) and (6,-5) -> slope is (-5--1)/(6-1) = -4/5 No match

(2,-1) and (10,9) -> slope is (9--1)/(10-2) = 10/8 = 5/4 Match!!

So the first and the last pairs are on perpendicular lines (not necessarily the same lines, as there are infinite possible perpendicular lines)

options A & E

Step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide